Codepath

2 Pointer Reverse List

Unit 4 Session 1 (Click for link to problem statements)

U-nderstand

Understand what the interviewer is asking for by using test cases and questions about the problem.

  • What should the function do with an empty list?
    • It should return an empty list as reversing an empty list is still empty.
  • What about lists with a single element?
    • The list should return unchanged as reversing it has no effect.

P-lan

Plan the solution with appropriate visualizations and pseudocode.

General Idea: Use two pointers to swap items from the start and end of the list moving towards the center.

1) Initialize two pointers: one at the beginning (`left`) and one at the end (`right`).
2) While `left` is less than `right`:
  a) Swap the elements at `left` and `right`.
  b) Move `left` pointer one step right (increase by 1).
  c) Move `right` pointer one step left (decrease by 1).
3) Return the list as the elements are now reversed in place.

⚠️ Common Mistakes

  • Not handling the case of an empty or single-element list correctly.
  • Incorrectly moving the pointers or failing to swap correctly, which can result in an incorrect list or infinite loop.

I-mplement

def reverse_list(lst):
    left = 0
    right = len(lst) - 1
    
    while left < right:
        # Swap elements using a temporary variable
        temp = lst[left]
        lst[left] = lst[right]
        lst[right] = temp
        
        # Move the pointers towards the center
        left += 1
        right -= 1
    
    return lst
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