TIP102 Unit 3 Session 1 Advanced (Click for link to problem statements)
Understand what the interviewer is asking for by using test cases and questions about the problem.
comfort_levels
representing the comfort levels of n
animals, where n
is an even number.Plan the solution with appropriate visualizations and pseudocode.
General Idea: Sort the list of comfort levels and use a two-pointer approach to pair the smallest and largest remaining comfort levels. This strategy minimizes the maximum comfort level among all possible pairs.
1. Sort the `comfort_levels` list in ascending order.
2. Initialize two pointers: `left` at the start of the list and `right` at the end of the list.
3. Initialize a variable `max_comfort_level` to keep track of the maximum comfort level encountered during the pairing process.
4. While `left` is less than `right`:
1. Pair the animal at the `left` pointer with the animal at the `right` pointer.
2. Calculate the comfort level for this pair and update `max_comfort_level` if this pair's comfort level is higher than the current `max_comfort_level`.
3. Move the `left` pointer one step to the right and the `right` pointer one step to the left.
5. Return the `max_comfort_level`, which will be the minimized maximum comfort level for the optimal pairing.
⚠️ Common Mistakes
comfort_levels
list before pairing.max_comfort_level
correctly, leading to incorrect results.def pair_up_animals(comfort_levels):
# Step 1: Sort the comfort levels
comfort_levels.sort()
# Step 2: Initialize two pointers
left = 0
right = len(comfort_levels) - 1
# Step 3: Initialize a variable to track the maximum pair comfort level
max_comfort_level = 0
# Step 4: Pair animals using the two-pointer approach
while left < right:
pair_comfort_level = comfort_levels[left] + comfort_levels[right]
# Update the maximum comfort level encountered
max_comfort_level = max(max_comfort_level, pair_comfort_level)
# Move the pointers
left += 1
right -= 1
# Step 5: Return the minimized maximum comfort level
return max_comfort_level
# Example usage
print(pair_up_animals([3,5,2,3])) # Output: 7
print(pair_up_animals([3,5,4,2,4,6])) # Output: 8