Unit 4 Session 1 Standard (Click for link to problem statements)
Understand what the interviewer is asking for by using test cases and questions about the problem.
Q: What is the structure of the input?
Q: What is the output?
Q: What should the function return if no such pair exists?
Q: How should ties be handled when multiple pairs have the same difference?
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Use a two-pointer approach to find the pair of memes whose combined popularity score is closest to the target value.
1) Initialize two pointers, `left` at the start and `right` at the end of the list.
2) Initialize variables `closest_pair` to store the closest meme pair and `closest_diff` to store the smallest difference found.
3) While `left` is less than `right`:
a) Calculate the combined popularity score of the memes at the `left` and `right` pointers.
b) Calculate the difference between this combined score and the target value.
c) If this difference is smaller than the current `closest_diff`, update `closest_diff` and `closest_pair`.
d) If the combined score is less than the target, move the `left` pointer to the right to increase the sum.
e) If the combined score is greater than or equal to the target, move the `right` pointer to the left to decrease the sum.
4) Return the `closest_pair` once the pointers meet.
**⚠️ Common Mistakes**
- Not updating the pointers correctly based on the comparison between the current sum and the target.
- Mismanaging the initialization or update of `closest_diff` and `closest_pair`.
def find_closest_meme_pair(memes, target):
left = 0
right = len(memes) - 1
closest_pair = ()
closest_diff = float('inf')
while left < right:
meme1, score1 = memes[left]
meme2, score2 = memes[right]
current_sum = score1 + score2
current_diff = abs(target - current_sum)
if current_diff < closest_diff:
closest_diff = current_diff
closest_pair = (meme1, meme2)
if current_sum < target:
left += 1
else:
right -= 1
return closest_pair